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A frictionless wire is fixed between A ...

A frictionless wire is fixed between `A` and `B` inside of a hollow sphere of radius `R` as shown. A bead slips along the wire starting from the rest at point `A`. The time taken by the bead to slip from `A` to `B` will be

A

`(2sqrt(gR))/(g cos theta)`

B

`2sqrt(gR).(cos theta)/(g)`

C

`2sqrt((R)/(g))`

D

`(gR)/(sqrt(g cos theta))`

Text Solution

Verified by Experts

The correct Answer is:
C
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