A body falls from rest, its velocity at the end of first second is `(g = 32 ft//sec)`

Options

A. `16 ft//sec`
B. `32 ft//sec`
C. `64ft//sec`
D. `24ft//sec`

Answer

To solve the problem of finding the velocity of a body falling from rest after the first second, we can use the following steps:

### Step 1: Understand the given values
- The body falls from rest, which means the initial velocity (u) is 0 ft/s.
- The acceleration due to gravity (g) is given as 32 ft/s².
- We need to find the final velocity (v) after 1 second (t = 1 s).

### Step 2: Use the formula for final velocity
The formula for final velocity when an object is in motion with constant acceleration is:
\[ v = u + g \cdot t \]

### Step 3: Substitute the known values into the formula
- Initial velocity (u) = 0 ft/s
- Acceleration (g) = 32 ft/s²
- Time (t) = 1 s

Substituting these values into the formula gives:
\[ v = 0 + 32 \cdot 1 \]
\[ v = 32 \text{ ft/s} \]

### Step 4: State the final answer
The velocity of the body at the end of the first second is **32 ft/s**.

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