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. A bullet moving with a velocity of 200...

. A bullet moving with a velocity of 200 cm / s penetrates a wooden block and comes to rest after traversing 4 cm inside it. What velocity is needed for travelling distance of 9cm in same block

A

100 m/s

B

136.2 cm/s

C

300 cm/s

D

250 cm/s

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the equations of motion. ### Step-by-Step Solution: 1. **Identify the Given Data:** - Initial velocity of the bullet, \( u = 200 \, \text{cm/s} \) - Final velocity of the bullet after penetrating 4 cm, \( v = 0 \, \text{cm/s} \) - Distance penetrated, \( s_1 = 4 \, \text{cm} \) - Distance to find the velocity for, \( s_2 = 9 \, \text{cm} \) 2. **Use the First Equation of Motion:** We will use the equation: \[ v^2 = u^2 + 2as \] Rearranging it for acceleration \( a \): \[ a = \frac{v^2 - u^2}{2s} \] 3. **Calculate the Acceleration (Retardation) when the bullet penetrates 4 cm:** Substituting \( u = 200 \, \text{cm/s} \), \( v = 0 \, \text{cm/s} \), and \( s_1 = 4 \, \text{cm} \): \[ a = \frac{0^2 - (200)^2}{2 \times 4} = \frac{-40000}{8} = -5000 \, \text{cm/s}^2 \] (The negative sign indicates retardation.) 4. **Use the Acceleration to Find the Required Velocity for 9 cm:** Now, we need to find the final velocity \( v \) when the bullet travels a distance of \( s_2 = 9 \, \text{cm} \). We will use the same equation: \[ v^2 = u^2 + 2as \] Here, the initial velocity \( u \) is the velocity we need to find, and \( a = -5000 \, \text{cm/s}^2 \) (retardation), and \( s = 9 \, \text{cm} \). 5. **Substituting the Values:** Since the bullet starts from rest in the block, we can assume \( u \) is the velocity we are trying to find: \[ v^2 = u^2 + 2(-5000)(9) \] \[ v^2 = u^2 - 90000 \] 6. **Setting the Equation for Final Velocity:** We need to find the value of \( u \) such that it comes to rest after traveling 9 cm. Thus, we set \( v = 0 \): \[ 0 = u^2 - 90000 \] \[ u^2 = 90000 \] \[ u = \sqrt{90000} = 300 \, \text{cm/s} \] ### Final Answer: The velocity needed for the bullet to travel a distance of 9 cm in the same block is **300 cm/s**.
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