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Pulling force making an angle theta to t...

Pulling force making an angle `theta` to the horizontal is applied on a block of weight `W` placed on a horizontal table. If the angle of friction is `alpha`, then the magnitude of force is `alpha` , then the magnitude of force required to move the body is equal to

A

`(Wsinalpha)/(gtan(theta-alpha))`

B

`(Wcosalpha)/(cos(theta-alpha))`

C

`(Wsinalpha)/(cos(theta-alpha))`

D

`(Wtanalpha)/(sin(theta-alpha))`

Text Solution

Verified by Experts

The correct Answer is:
C
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