Home
Class 11
PHYSICS
A block of mass 10 kg is placed on an in...

A block of mass 10 kg is placed on an inclined plane when the angle of inclination is `30^(@)`. The block just begins to slide down the plane. The force of static friction is

A

10 kg wt

B

89 kg w

C

49 kg wt

D

5 kg wt

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • FLUID MECHANICS

    ERRORLESS |Exercise Fluid Mechanics|19 Videos

  • GRAVITATION

    ERRORLESS |Exercise SET|27 Videos

Similar Questions

Explore conceptually related problems

A block of mass 5 kg rests on a inclined plane at an angle of 30^(@) with the horizontal. If the block just begins to slide, then what is the coefficient of static friction between the block and the surface?

A block of mass 5 kg rests on a inclined plane at an angle of 30^(@) with the horizontal . If the block just begins to slide , then what is the coefficient of static friction between the block and the surface ?

Knowledge Check

  • A block of mass m is placed on a rough inclined plane. When the inclination of the plane is theta , the block just beging to slide down the plane under its own weight. The minimum force applied parallel to the plane, to move the block up the plane, is.

    A
    `mgsintheta`
    B
    `2mgsintheta`
    C
    `mgcostheta`
    D
    `mg tantheta`

  • A block of mass 5 kg is placed on a rough inclined plane. The inclination of the plane is gradually increased till the block just begins to slide down. The inclination of the plane is than 3 in 5. The coefficient of friction between the block and the plane is (Take, g = 10m//s^(2) )

    A
    `(3)/(5)`
    B
    `(3)/(4)`
    C
    `(4)/(5)`
    D
    `(2)/(3)`

  • A block of mass 4kg rests on an an inclined plane. The inclination of the plane is gradually increased. It is found that when the inclination is 3 in 5 (sin=theta(3)/(5)) the block just begins to slide down the plane. The coefficient of friction between the block and the plane is.

    A
    `0.4`
    B
    `0.6`
    C
    `0.8`
    D
    `0.75`

    • Similar Questions

    Explore conceptually related problems

    A block of mass 10 kg is kept on a fixed rough (mu=0.8) inclined plane of angle of inclination 30^(@) . The frictional force acting on the block is

    A block is placed on an inclined plane. The angle of inclination of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is

    A block of mas M is resting on an inclined plane as shown in the figure. The inclination of the plane to the horizontal is gradually increased. It is found that when the angle of inclination is theta the block just begins to slide down the plane. What is the minimum force F applied parallel to the plane that would just make the block move up the plane ?

    A block of mas m begins to slide down on an inclined plane of inclination theta . The force of friction will be

    A block of mass 5 kg and surface area 2m^(2) just begins to slide down an inclined plane when the angle on inclination is 30^(@) . Keeping mass same, the surface area of the block is doubled. The angle is which this starts sliding down is

    Home
    Profile