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sum(i=1)^(20)((^20C(i-1))/(20C(i)+^(20)C...

sum_(i=1)^(20)((^20C_(i-1))/(20C_(i)+^(20)C_(i-1)))^(3)=(k)/(21)" then k equals "

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sum_(k=0)^20(.^20C_k)^2 = ?