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Two wires of copper having the length in...

Two wires of copper having the length in the ratio `4 : 1` and their radii ratio as `1 : 4` are stretched by the same force. The ratio of longitudinal strain in the two will be

A

`1:16`

B

`16:1`

C

`1:64`

D

`64:1`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the ratio of longitudinal strain in two copper wires given their lengths and radii ratios. Let's break it down step by step. ### Step 1: Understand the Given Ratios - The lengths of the two wires are in the ratio \( L_1 : L_2 = 4 : 1 \). - The radii of the two wires are in the ratio \( R_1 : R_2 = 1 : 4 \). ### Step 2: Define Longitudinal Strain Longitudinal strain (\( \epsilon \)) is defined as the change in length per unit length, which can be expressed as: \[ \epsilon = \frac{\text{Stress}}{Y} \] where \( Y \) is the Young's modulus of the material. ### Step 3: Define Stress Stress (\( \sigma \)) is defined as the force applied per unit area. For a wire with a circular cross-section, the area \( A \) is given by: \[ A = \pi R^2 \] Thus, the stress can be expressed as: \[ \sigma = \frac{F}{A} = \frac{F}{\pi R^2} \] ### Step 4: Write the Expression for Longitudinal Strain Substituting the expression for stress into the equation for longitudinal strain, we have: \[ \epsilon = \frac{F}{\pi R^2 Y} \] ### Step 5: Calculate the Ratio of Longitudinal Strain Since both wires are made of the same material (copper), their Young's modulus \( Y \) will be the same. Therefore, we can write the ratio of the strains in the two wires as: \[ \frac{\epsilon_1}{\epsilon_2} = \frac{\frac{F}{\pi R_1^2 Y}}{\frac{F}{\pi R_2^2 Y}} = \frac{R_2^2}{R_1^2} \] ### Step 6: Substitute the Values of Radii From the given ratio \( R_1 : R_2 = 1 : 4 \), we can express \( R_2 \) in terms of \( R_1 \): \[ R_2 = 4R_1 \] Now substituting this into the ratio of strains: \[ \frac{\epsilon_1}{\epsilon_2} = \frac{(4R_1)^2}{(R_1)^2} = \frac{16R_1^2}{R_1^2} = 16 \] ### Conclusion Thus, the ratio of longitudinal strain in the two wires is: \[ \frac{\epsilon_1}{\epsilon_2} = 16 : 1 \]
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