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Young's modulus of rubber is 10^(4) N//m...

Young's modulus of rubber is `10^(4) N//m^(2)` and area of cross section is `2 cm^(2)`. If force of `2 xx 10^(5) dyn` is applied along its length, then its final length becomes

A

3 L

B

4 L

C

2 L

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
C
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