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The relation betweent gamma,eta and K fo...

The relation betweent `gamma,eta` and K for a elastic material is

A

`(1)/(eta)=(1)/(3 gamma)+(1)/(3K)`

B

`(1)/(K)=(1)/(3gamma)+(1)/(9 eta)`

C

`(1)/(gamma)=(1)/(3K)+(1)/(9eta)`

D

`(1)/(gamma)=(1)/(3 eta)+(1)/(9K)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the relationship between Young's modulus (γ), modulus of rigidity (η), and bulk modulus (K) for an elastic material, we can follow these steps: ### Step 1: Identify the Moduli We start by identifying the moduli: - Let γ = Young's modulus - Let η = Modulus of rigidity (shear modulus) - Let K = Bulk modulus ### Step 2: Write the Relationships We know the following relationships for elastic materials: 1. Young's modulus (γ) can be expressed in terms of bulk modulus (K) and shear modulus (η): \[ \gamma = 3K(1 - 2\sigma) \] where σ is the Poisson's ratio. 2. Young's modulus (γ) can also be expressed in terms of shear modulus (η): \[ \gamma = 2η(1 + α) \] where α is the coefficient of linear expansion. ### Step 3: Set Up the Equations From the above relationships, we can set up two equations: 1. \(\frac{\gamma}{3K} = 1 - 2\sigma\) (Equation 1) 2. \(\frac{\gamma}{2η} = 1 + α\) (Equation 2) ### Step 4: Manipulate the Equations We can manipulate these equations to express σ and α in terms of γ, K, and η. From Equation 1: \[ \sigma = \frac{1}{2} \left( 1 - \frac{\gamma}{3K} \right) \] From Equation 2: \[ α = \frac{\gamma}{2η} - 1 \] ### Step 5: Substitute and Combine Now, we can substitute these expressions into one another to eliminate σ and α. ### Step 6: Combine the Equations Multiply Equation 2 by 2: \[ \frac{\gamma}{η} = 2 + 2α \] Substituting for α: \[ \frac{\gamma}{η} = 2 + 2\left(\frac{\gamma}{2η} - 1\right) \] ### Step 7: Solve for η Now, we can rearrange this equation to solve for η in terms of γ and K: \[ \frac{\gamma}{η} = 2 + \frac{\gamma}{η} - 2 \] This simplifies to: \[ \frac{1}{η} = \frac{3}{\gamma} + \frac{1}{9K} \] ### Step 8: Final Relationship Rearranging gives us the final relationship: \[ 3η + \frac{1}{9K} = \frac{1}{γ} \] ### Conclusion Thus, the relationship between Young's modulus (γ), modulus of rigidity (η), and bulk modulus (K) is: \[ 3η + \frac{1}{9K} = \frac{1}{γ} \]
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