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If the force constant of a wire is K, th...

If the force constant of a wire is K, the work done in increasing the length of the wire by `l` is

A

`K//2`

B

`Kl`

C

`Kl^(2)//2`

D

`Kl^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the work done in increasing the length of a wire by a distance \( l \) when the force constant (spring constant) of the wire is \( K \), we can follow these steps: ### Step 1: Understand the relationship between force and extension The force constant \( K \) of a wire is defined as: \[ K = \frac{F}{l} \] where \( F \) is the force applied to stretch the wire and \( l \) is the extension (increase in length) of the wire. ### Step 2: Express the force in terms of the force constant and extension From the equation above, we can rearrange it to express the force \( F \): \[ F = K \cdot l \] ### Step 3: Use the formula for work done The work done \( W \) in stretching the wire can be expressed as the potential energy stored in the wire when it is stretched. The formula for the potential energy (or work done) in stretching a spring (or wire) is given by: \[ W = \frac{1}{2} \cdot F \cdot l \] ### Step 4: Substitute the expression for force into the work done formula Now substitute \( F = K \cdot l \) into the work done formula: \[ W = \frac{1}{2} \cdot (K \cdot l) \cdot l \] ### Step 5: Simplify the expression This simplifies to: \[ W = \frac{1}{2} \cdot K \cdot l^2 \] ### Final Answer Thus, the work done in increasing the length of the wire by \( l \) is: \[ W = \frac{1}{2} K l^2 \]
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