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A vertical column 50 cm long at 50^(@)C ...

A vertical column 50 cm long at `50^(@)C` balances another column of same liquid 60 cm long at `100^(@)C` . The coefficient of absolute expansion of the liquid is

A

`0.005//^(@)C`

B

`0.0005//^(@)C`

C

`0.002//^(@)C`

D

`0.0002//^(@)C`

Text Solution

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The correct Answer is:
To find the coefficient of absolute expansion of the liquid, we can follow these steps: ### Step 1: Understand the relationship between density, volume, and temperature The density of a liquid changes with temperature. The volume \( V \) of a liquid at a temperature \( T \) can be expressed as: \[ V = V_0 (1 + \gamma T) \] where \( \gamma \) is the coefficient of volumetric expansion, and \( V_0 \) is the volume at 0°C. ### Step 2: Set up the relationship between the two columns of liquid Given that the first column of liquid is 50 cm long at 50°C and balances with a 60 cm long column at 100°C, we can express the densities of the two columns: - For the first column at 50°C: \[ \rho_1 = \frac{m}{V_1} = \frac{m}{V_0(1 + \gamma \cdot 50)} \] - For the second column at 100°C: \[ \rho_2 = \frac{m}{V_2} = \frac{m}{V_0(1 + \gamma \cdot 100)} \] ### Step 3: Use the balance condition Since the two columns balance each other, we can set up the equation: \[ \rho_1 \cdot g \cdot 50 = \rho_2 \cdot g \cdot 60 \] Cancelling \( g \) from both sides gives: \[ \rho_1 \cdot 50 = \rho_2 \cdot 60 \] This can be rearranged to: \[ \frac{\rho_1}{\rho_2} = \frac{60}{50} = \frac{6}{5} \] ### Step 4: Substitute the expressions for densities Substituting the expressions for \( \rho_1 \) and \( \rho_2 \): \[ \frac{\frac{m}{V_0(1 + \gamma \cdot 50)}}{\frac{m}{V_0(1 + \gamma \cdot 100)}} = \frac{6}{5} \] This simplifies to: \[ \frac{1 + \gamma \cdot 100}{1 + \gamma \cdot 50} = \frac{6}{5} \] ### Step 5: Cross-multiply and solve for \( \gamma \) Cross-multiplying gives: \[ 5(1 + \gamma \cdot 100) = 6(1 + \gamma \cdot 50) \] Expanding both sides: \[ 5 + 500\gamma = 6 + 300\gamma \] Rearranging terms: \[ 500\gamma - 300\gamma = 6 - 5 \] This simplifies to: \[ 200\gamma = 1 \] Thus: \[ \gamma = \frac{1}{200} \] ### Step 6: Convert to the required units The coefficient of volumetric expansion \( \gamma \) is: \[ \gamma = 0.005 \, \text{per degree Celsius} \] ### Final Answer The coefficient of absolute expansion of the liquid is \( \gamma = 0.005 \, \text{per degree Celsius} \). ---
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ERRORLESS -THERMOMETRY, THERMAL EXPANSION AND CALORIMETRY -Thermal Expansion
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