Calculate the amount of heat (in calorie...

Calculate the amount of heat (in calories) required to convert `5 gm` of ice at `0^(@)C` to steam at `100^(@)C`

3100

3200

3600

4200

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Heat required to convert 1 g of ice at 0^(@)C into steam at 100 ^(@)C is

The amount of heat (in calories) required to convert 5g of ice at 0^(@)C to steam at 100^@C is [L_("fusion") = 80 cal g^(-1), L_("vaporization") = 540 cal g^(-1)]

What is the amount of heat required (in calories) to convert 10 g of ice at -10^(@)C into steam at 100^(@)C ? Given that latent heat of vaporization of water is "540 cal g"^(-1) , latent heat of fusion of ice is "80 cal g"^(-1) , the specific heat capacity of water and ice are "1 cal g"^(-1).^(@)C^(-1) and "0.5 cal g"^(-1).^(@)C^(-1) respectively.

Calculate the amount of heat required to convert 10g of water at 30^(@)C into steam at 100^(@)C . ( Specific latent heat of vaporization of water = 540 cal//g )

Calculate the amount of heat required to con-vert 10 g of ice at 0^(@)C to 10 g of water at 100^(@)C (Specific heat capacity of water =1 cal/g/ ""^(@ )C )

Calculate the amount of heat required in calorie to change 1 g of ice at -10^(@)C to steam at 120^(@)C . The entire process is carried out at atmospheric pressure. Specific heat of ice and water are 0.5 cal g^(-1) .^(@)C^(-1) and 1.0 cal g^(-1) .^(@)C^(-1) respectively. Latent heat of fusion of ice and vaporization of water are 80 cal g^(-1) and 540 cal g^(-1) respectively. Assume steam to be an ideal gas with its molecules having 6 degrees of freedom. Gas constant R = 2 cal mol^(-1) K^(-1) .

ERRORLESS -THERMOMETRY, THERMAL EXPANSION AND CALORIMETRY -Calorimetery

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