(dy)/(dx)+(1)/(x)tan y=(1)/(x^(2))tan y sin y" is "

The solution of the equation (dy)/(dx) +1/xtany =(1)/(x^(2))tan y sin y is:

(dy)/(dx)=1+x tan(y-x)

(dy) / (dx) tan y = sin (x + y) + sin (xy)

(dy)/(dx)=y tan x , y=1 when x=0

If (dy)/(dx)+y tan x=sin2x and y(0)=1, then y(pi) is equal to:

If (dy)/(dx)+y tan x=sin2x and y(0)=1 , then y(pi) is equal to :

Solve the differential equation: (i) (1+y^(2))+(x-e^( tan ^(-1)y))(dy)/(dx)=0 (ii) x(dy)/(dx)+cos^(2)y=tan y(dy)/(dx)