`ABCDE` is a regular pentagon and bisector of `BAE` meets `CD` at` M,` bisector of `BCD `meets `AM` at `P`. Prove that `CPM = 36^@.`

ABCDE is a regular pentagon and bisector of /_BAE meets CD at M. If bisector of /_BCD meets AM at P, find /_CPM.

ABCDE is a regular pentagon. Angle bisector of angle BAE meets CD at m. angle bisector of angle BCD meets AM at P. Find the angle CPM = ?

A B C D E is a regular pentagon and bisector of /_B A E\ meets C D\ at Mdot If bisector of /_B C D meets A M at P , find /_C P Mdot

ABCDE is a regular pentagon. The bisector of angle A meets the side CD at M. Find angle AMC

ABCDE is a regular pentagon.The bisector of angle A meets side CD at P, then prove that APC=90^(@).

ABCDE is a regular pentagon.The bisector of /_A of the pentagon meets the side CD in M* Show that /_AMC=90^(@).

ABCDE is a regular pentagon. The bisector of angle A of the pentagon meet the side CD in point M. Show that angleAMC=90^@ .

A B C D E is a regular pentagon. The bisector of /_A of the pentagon meets the side C D in Mdot Show that /_A M C=90^0dot

Triangle ABC is similar to triangle PQR. If bisector of angle BAC meets BC at point D and bisector of angle QPR meets QR at point M, prove that : (AB)/(PQ) = (AD)/(PM)

In a ABC, the internal bisectors of /_B and /_C met at P and the external bisectors of /_B and /_C meet at Q. Prove that /_BPC+/_BQC=180^(@)