An 'n' digit number is constructed using only the digit 1.2,3 or4 such that it contain the digit 1 either an even number of times or not at all. If the number of such'n' digit Legitimate number are 136 then the value of n equals

The number of n digit number formed by using digits {1,2,3} such that if 1 appears, it appears even number of times, is

The number of n digit number formed by using digits {1,2,3} such that if 1 appears, it appears even number of times, is

The number of n digit number formed by using digits {1,2,3} such that if 1 appears, it appears even number of times, is

If two digit number are formed using the digits 0, 1, 2, 3, 4, 5 with repeating them, then n(S) =

If two digit number are formed using the digits 0, 1, 2, 3, 4, 5 with repeating them, then n(S) =

Let a_n denote the number of all n-digit positive integers formed by the digits 0, 1, or both such that no consecutive digits in them are 0. Let b_n= The number of such n-digit integers ending with digit 1 and c_n= Then number of such n-digit integers with digit 0. The value of b_6 is

Find the number of n digit numbers, which contain the digits 2 and 7, but not the digits 0, 1, 8, 9.

Find the number of n digit numbers, which contain the digits 2 and 7, but not the digits 0, 1, 8, 9.