|[b^(2)c^(2),bc,b+c],[c^(2)a^(2),ca,c+a],[a^(2)b^(2),ab,a+b]|

|[b^(2)c^(2),bc,a-c],[c^(2)a^(2),ca,b-c],[a^(2)b^(2),ab,0]|=?

If a,b,c are non-zero real numbers then D=det[[b^(2)c^(2),bc,b+cc^(2)a^(2),ca,c+aa^(2)b^(2),ab,a+b]]=(A)abc(B)a^(2)b^(2)c^(2)(C)bc+ca+ab(D)0,

Prove that [[b^2c^2, bc,b+c],[c^2a^2,ca,c+a],[a^2b^2,ab,a+b]] = 0

|[b^2c^2,bc,b+c] , [c^2a^2,ca,c+a] , [a^2b^2,ab,a+b]|=0

Without expanding, prove that the following determinants vanish: {:|(b^2c^2,bc,b+c),(c^2a^2,ca,c+a),(a^2b^2,ab,a+b)|

Without expanding prove that, |{:(b^2c^2,bc,b+c),(c^2a^2,ca,c+a),(a^2b^2,ab,a+b):}|=0

Show that |(b+c,bc,b^(2)c^(2)),(c+a,ca,c^(2)a^(2)),(a+b,ab,a^(2)b^(2))|=0 .

Without expanding,show that the following determinant vanishes. abs((b^2c^2,bc,b+c),(c^2a^2,ca,c+a),(a^2b^2,ab,a+b))

Show that |{:(b+c,bc,b^(2)c^(2)),(c+a,ca,c^(2)a^(2)),(a+b,ab,a^(2)b^(2)):}| = 0