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Two point A and B are situated at distan...

Two point A and B are situated at distance 1 m and 2m form the source of an electrostatic field. The field at a distance x from the source is `E = (5)/(x^2)`. What is the potential difference between A and B?

Text Solution

Verified by Experts

We know that, `E = (dV)/(dx)`
Here, `E = 5/(x^2)`
`:. 5/(x^2) = -(dV)/(dx) "or", dV = -5(x^2)dx`
`:. V_(A) - V_(B) = int_(2)^(1) -5/(x^2) dx = -5[-1/x]_(2)^(1)`
`=5(1-1/2) = 5/2 = 2.5` units.
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