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An electric dipole of moment 5 xx 10^(-8...

An electric dipole of moment `5 xx 10^(-8)C cdot m` is placed in an electric field of magnitude `4 xx 10^(5) N cdot C^(-1)`. What amount of work is to be done to deflect it through an angle `60^(@)` ?

Text Solution

Verified by Experts

We know, work done
`W = pE(1-cos theta)`
`=5xx10^(-8)xx4xx10^(5)(1-cos 60^(@))`
Here, `p = 5 xx 10^(-8)C cdot m, E = 4 xx 10^(5) N cdot C^(-1), theta = 60^(@)`
`:. W = 2 xx 10^(-2) (1-0.5)`
`=10^(2) J`.
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