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Two point charges of values -20 esu and ...

Two point charges of values -20 esu and +20 esu are placed on the x-axis at `x = -10cm and x = +10cm` respectively. Calculate
The potentials at the middle of them

Text Solution

Verified by Experts

Two charges + 20 esu and -20 esu are placed at A and B respectively.
(i) Coordinates of P are (0,10).
Thus, `AP = BP = sqrt(10^(2)+10^(2)) = 10sqrt(2)cm`.

Potential at `P, V_(P) = -(20)/(AP) + (20)/(BP) = 0`
Coordinates of Q are (20,0).
So, `AQ = 30 cm and BQ = 10 cm`
Thus potential at Q,
`V_(Q) = 20/(BQ) - 20/(AQ) = 20/10 - 20/30 = 4/3 = 1.33 esu`.
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