Home
Class 12
PHYSICS
In a hydrogen atom, the electron and pro...

In a hydrogen atom, the electron and proton are bound at a distance of about 0.53 Å.
(a) Estimate the potential energy of the system in eV, taking the zero of the potential energy at infinite separation of the electron from proton.
(b) What is the minimum work to free the electron, given that its kinetic energy in the orbit is half the magnitude of potential energy obtained in (a)?

Text Solution

Verified by Experts

Kinetic energy of the electron,
`E_(K) = 1/2 E_(P) = 13.585 eV [E_(k)` is always positive]
`:.` total energy of the electron,
`E = E_(P)+E_(K) = (-27.17 + 13.585)eV`
`=-13.585 eV`.
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC POTENTIAL

    CHHAYA PUBLICATION|Exercise NCERT examplar questions with answer hint (MCQ -1 single option correct)|3 Videos

  • ELECTRIC POTENTIAL

    CHHAYA PUBLICATION|Exercise NCERT examplar questions with answer hint (MCQ -2 Multiple options correct)|3 Videos

  • ELECTRIC POTENTIAL

    CHHAYA PUBLICATION|Exercise Higher order thinking skill (HOTS) questions|23 Videos

  • ELECTRIC FIELD

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|31 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|28 Videos

Similar Questions

Explore conceptually related problems

An one -electron atom has an energy of -3.4 eV. The potential energy of the electron is

Define kinetic energy and potential energy.

What is the significance of negative energy of electron in its orbit ?

A hydrogen atom rises from its n=1 state to the n=4 state by absorbing energy . If the potential energy of the atom in the n=1 state by -13.6 eV ,then calculate the (i) potential energy in n=4 state

The total energy of an electron in the first excited state of hydrogen atom is -3.4 eV . What is the potential energy of the electron in this state ?

Show that kinetic energy of an electron in the first Bohr orbit is numerically half of its potential energy.