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The work done to move a charge along an ...

The work done to move a charge along an equipotential from A to B

A

cannot be defined as `-int_(A)^(B) vec(E ) cdot dvec(l)`

B

must be defined as `-int_(A)^(B) vec(E ) cdot dvec(l)`

C

is zero

D

can have a non - zero value

Text Solution

Verified by Experts

The correct Answer is:
B, C
`W = int_(A)^(B) vec(E ) cdot dvec(l) = -int_(A)^(B) Edlcos theta`
For equipotential surface, `theta = 90^(@)`
So, `W = 0`.
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