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Find the electric field and potential at...

Find the electric field and potential at the centre of curvature of a uniformly charged semicircular rod of radius R with a total charge Q in SI. `lambda` is the linear charge density.

Text Solution

Verified by Experts

The correct Answer is:
`(Q/(2pi^(2)epsilon_(0)R^(2)), (lambda)/(4epsilon_(0)))`
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