The diameter of a spherical liquid drop is 2 mm and its charge is `5 xx 10^(-6)` esu.
What is the potential on its surface?

Explanation

Is CGS system, radius of the spherical conductor = its capacitance (numerically).
Capacitance fo the spherical liquid drop,
`C = 0.1 statF [ :. " Radius " = 1mm = 0.1 cm]`
Potential on the surface of the liquid drop,
`V = (Q)/(C )= (5 xx 10^(-6))/(0.1) = 5 xx 10^(-5)` statV
`= 5 xx 10^(-5) xx 300 V= 0.015V`.