The capacitance and potential, respectively, of a conductor A are 10 unit 50 unit, those of another conductor B are, respectively, 5 unit and 65 unit. Find out the charges on the two conductors after they are connected by a conductiong wire.

Explanation

Initially, charge on conductor A,
`Q_1= C_1V_1= 10xx50=500` unit and charge on conductor B,
`Q_2=C_2V_2= 5xx65=325` unit
`V=(Q_1+Q_2)/(C_1+C_2)=(500+325)/(10+5)=(825)/(15)=55`unit
Now, charge on conductor A,
`q_1=C_1V= 10xx55 = 550` unit
and charge on conductor B,
`q_2= C_2V = 5xx55 = 275` unit.