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The plates of a parallel plate capacitor...

The plates of a parallel plate capacitor have an area of 90 `cm^2` each and are separated by 5.5 mm. The capacitor is charged by connecting it to a 400 V supply.
Arrive at a relation between u and the magnitude of electric field between the two plates.

Text Solution

Verified by Experts

Capacitance, `C= (in_0 alpha)/(d) = (8.854xx10^(-12) 90xx10^(-4))/(2.5xx10^(-3))= 3.187 xx10^(-11)F`
`u = ((1/2)CV^2)/(alpha d)= (1)/(2) (C )/(alphad)*(Ed)^2 " "[:. E = (V)/(d)]`
`= (1)/(2)*(in_0 alpha)/(d)* (E^2d^2)/(alpha d)= (1)/(2) in_0 E^2`.
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