Home
Class 12
PHYSICS
After charging a capacitor, the battery ...

After charging a capacitor, the battery is disconnected. What would be the nature of change of its capacitance, potential difference between the plates, and energy stored if
the distance between the two plates decreases.

Promotional Banner

Topper's Solved these Questions

  • CAPACITANCE AND CAPACITOR

    CHHAYA PUBLICATION|Exercise PROBLEM SET - I|33 Videos
  • CAPACITANCE AND CAPACITOR

    CHHAYA PUBLICATION|Exercise PROBLEM SET - II|29 Videos
  • CAPACITANCE AND CAPACITOR

    CHHAYA PUBLICATION|Exercise SHORT ANSWER TYPE QUESTIONS- I|9 Videos
  • ATOMIC NUCLEUS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|14 Videos
  • COMMUNICATION STSTEM

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|28 Videos

Similar Questions

Explore conceptually related problems

After charging a capacitor, the battery is disconnected. What would be the nature of change of its capacitance, potential difference between the plates, and energy stored if the two plates are connected by a conducting wire?

After charging a capacitor, the battery is disconnected. Now a dielectric material is introduced between its two plates. What would be the nature of change of its charge, capacitance, potential difference, electric field, energy stored?

The separation between the plates of a parallel plate capacitor is t, and the intervening space is filled with glass, of dielectric constant 6. Now, the separation between the plates is increased by t. How would the charge on the capacitor and the potential difference between its plates charge, if The battery is disconnected before increasing the separation between the plates?

A capacitor is charged by a battery and then disconnected.How are the capacitance, potential difference and stored energy related to the capacitor affected if The plates are connected by a metallic wire?

If the potential difference between the plates of a capacitor is increased by 20%, the energy stored in the capacitor increase by exactly

The separation between the plates of a parallel plate capacitor is t, and the intervening space is filled with glass, of dielectric constant 6. Now, the separation between the plates is increased by t. How would the charge on the capacitor and the potential difference between its plates charge, if The plates remain connected with the charging battery

A parallel plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected. A slab of dielectric constant k is then inserted between the plates of the capacitor so as to fill the space between the plates. If Q, E and W denote respectively the charge on each plate, the electric field between the plates and the work done in the process of inserting the slab, then