A parallel plate air capacitor of plate separation d is charged to a potential difference `triangle V `. A slab of thickness d and dielectric constant k is introduced between the plates while the battery remains connected.
Find the ratio of energy stored in the capacitor after and before the introduction of the dielectric slab.

A parallel plate air capacitor of plate separation d is charged to a potential difference triangle V . A slab of thickness d and dielectric constant k is introduced between the plates while the battery remains connected. What happens to the charge on the capacitor?

A parallel plate capacitor has a capacitance of 100muF . The plates are at a distance d apart. A slab of thickness t(t = d) and dielectric constant 5 is introduced between the parallel plates. Then capacitance can be,

A parallel plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected. A slab of dielectric constant k is then inserted between the plates of the capacitor so as to fill the space between the plates. If Q, E and W denote respectively the charge on each plate, the electric field between the plates and the work done in the process of inserting the slab, then

What will be the change in the capacitance of a parallel plate air capacitor if A dielectric slab.

A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20V. If a dielectric material of dielectric constant k=(5)/(3) is inserted between the plates, the magnitude of the induced charge will be

The figure shows two identical parallel plate capacitor connected to a battery with the switch S closed. The switch is now opened and the free space between the plates of the capacitor is filled with a dielectric of dielectric constant 3. Find the ratio of the total electrostatic energy stored in both capacitors before and after the introduction of the dielectric.

A parallel plate air capacitor has a capacitance C and the distance between the plates is d.A metallic plate of thickness d/3 is introduced between the plates of the capacitor. The new capacitance will be—

A dielectric slab is inserted between the plates of a capacitor. The charge on the capacitor is Q and the magnitude of the induced charge on each surface of the dielectric is Q'

A parallel plate air capacitor has capacity 'C' distance of separation between plates is ‘d’ and potential difference 'V' is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor is