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A slab of material of dielectric constan...

A slab of material of dielectric constant k has the same area as the plates of parallel plate capacitor, but has a thickness `(3)/(4)d` , where d is the separation of the plates. How is the capacitance changed when the slab is inserted between the plates?

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`(4k)/(k+3)xx` initial capacitance = final capacitance.
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CHHAYA PUBLICATION-CAPACITANCE AND CAPACITOR-PROBLEM SET - II
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  2. The separation between the plates of a parallel plate capacitor is t, ...

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  3. A slab of material of dielectric constant k has the same area as the p...

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  9. The capacitances of two capacitors are 2 mu F and 8 mu F. They are con...

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  10. A capacitor of capacitance 2 mu F is charged with 20 V potential. Anot...

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  11. The capacitance of a conductor is 2 pF and its potential is 100 V. Whe...

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  12. The equivatent capacitance between A and B for the combination of Fig....

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  13. The equivatent capacitance between A and B for the combination of Fig....

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  14. A network of four 10 mu F capacitors is connected to a 500 V supply, a...

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  15. Two parallel plates of area 100 cm^2 are given equal and opposite char...

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  16. Two parallel plates of area 100 cm^2 are given equal and opposite char...

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  17. The distance between the two plates of a parallel plate air capacitor ...

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  18. The distance between the two plates of a parallel plate air capacitor ...

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  19. The separation between the plates, each having an area of 1 m^2, of a ...

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  20. The separation between the two plates, each having an area of 100 pi^2...

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