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Resistance of the ratio arms of a Wheatstone brige are `100Omega and 10Omega` respectively . An unknown resistance is placed n fourth arm and the galvanometer current becomes zero when `153Omega` resistance is placed in third arm . What is value of unknown resistance ?

Text Solution

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Here , `p=100Omega,Q=10OmegaandR=153Omega`
Since , `(P)/(Q)=(R)/(S)thereforeS=(RQ)/(P)=(153xx10)/(100)=15.3Omega`
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CHHAYA PUBLICATION-KIRCHHOFF'S LAWS AND ELECTRICAL MEASUREMENT -CBSE SCANNER
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