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In a Wheatstone bridge, a 15Omega resis...

In a Wheatstone bridge, a `15Omega` resistance and an unknown resistance are placed in third arm and fourth arm respectively . Current through galvanometer becomes zero when ratio of resistance of first and second arms is `3:2` , Find the value of unknown resistance .

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Here , `R=15Omegaand(P)/(Q)=(3)/(2)`
Since , `(P)/(Q)=(R)/(S)thereforeS=R.(Q)/(P)=15xx(2)/(3)=10Omega`
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CHHAYA PUBLICATION-KIRCHHOFF'S LAWS AND ELECTRICAL MEASUREMENT -CBSE SCANNER
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