How will the position of null ponit of a Wheatstone bridge change if we interchange the battery and galvanometer in the circuit ?

Explanation

Suppose , the battery is connected between the points A and B of the Wheatstone bridge and the galvanometer is connected between the positions of the battery and the galvanometer is connected between the points C and D . Then the null condition of the brige is ,
`(P)/(Q)=(R)/(S)`
Next the battery is connected between the points C and D and the galvanometer is connected between the points A and B . In this first , seond thrird and fourth arms of the brige are R , P ,S and Q respectively . so the null connected of the bridge now is
`(R)/(P)=(S)/(Q) " or , " (P)/(Q)=(R)/(S)` Obviously , in both the cases the null condition is exatly the same , i.e due to the interchage of battery and the galvanometer the null condition of the bridge does not change .