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A potentiometer wire has length 4m and r...

A potentiometer wire has length 4m and resistance `8Omega` the resistance that must be connected in series with the wire and an accumulaterof emf 2 V so as to get a potential gradient 1 mV ,per cm on the wire is

A

`32Omega`

B

`40Omega`

C

`44Omega`

D

`48Omega`

Text Solution

Verified by Experts

The correct Answer is:
A

Resistance of the potentimeter wire of lengh 1cm
`(8Omega)/(400"cm")=(1)/(50)Omega//"cm"`
If the potential differnce at the two ends of 1 cm portion `1mV" or " 10^(-3)V,`
then the current through the wire , `I=(10^(-3))/((1)/(50))=(1)/(20)A`
For the entire circuit , `I=(E)/(R_(P)+R)`
`"or, "R=(E)/(I)-R_(P)=(2)/((1)/(20))-8=32Omega`
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