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2 A current was sent through a coil of r...

2 A current was sent through a coil of resistance `100Omega` for 30 min .Determine the amount of heat produced , the quantity of charge passed and the amount of work doen.

Text Solution

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Here , `I=2A,R=100Omega,t=30 "min"=30xx60s`
The amount of heat produced ,
`H=(I^(2)Rt)/(J)=((2^(2))xx100xx30xx60)/(4.2)` ltbrge `1.71xx10^(5)"cal"`
The quantity of cahrge flowing,
`Q=It=2xx30xx60=3600C`
The amount of work done ,
`W=QV=QIR=3600xx2xx100=7.2xx10^(5)J`
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