Home
Class 12
PHYSICS
A cell of emf 1.5 V and of internal resi...

A cell of emf 1.5 V and of internal resistance `0.1Omega` when connected with a resitor and an ammeter of negligible resistance in series , the ammeter shows a 2.0 A steady current .
Find (ii) the power consumed in the resistor .

Text Solution

Verified by Experts

`I=(E)/(R+r),R=` resistance of the resistor
`"or,"R=(E)/(I)-r=(1.5)/(2)-0.1=0.65Omega`
`therefore` Power consumed in the resistor,
`I^(2)R=(2.0)^(2)xx0.65=2.6W`
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC ENERGY AND POWER

    CHHAYA PUBLICATION|Exercise Section Related Questions|21 Videos

  • ELECTRIC ENERGY AND POWER

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILL (HOTS)QUESTIONS|17 Videos

  • DIGITAL CIRCUITS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|6 Videos

  • ELECTRIC FIELD

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|31 Videos

Similar Questions

Explore conceptually related problems

A cell of emf 1.5 V and of internal resistance 0.1Omega when connected with a resitor and an ammeter of negligible resistance in series , the ammeter shows a 2.0 A steady current . Find (i) the rate of energy dissipated within the cell

A cell of emf 1.4V and internal resistance 2 Omega is connected in series with a resistance of 100 Omega and an ammeter. The resistance of the ammeter is 4/3 Omega .To measure the potential difference between the two ends of the resistance a voltmeter is connected IF the reading of the ammter is 0.02 A.what is the resistance of the voltmeter?

A cell of emf 1.4V and internal resistance 2 Omega is connected in series with a resistance of 100 Omega and an ammeter. The resistance of the ammeter is 4/3 Omega .To measure the potential difference between the two ends of the resistance a voltmeter is connected IF the reading of the voltmeter is 1.10V, what will be its error?

A cell of emf 1.4V and internal resistance 2 Omega is connected in series with a resistance of 100 Omega and an ammeter. The resistance of the ammeter is 4/3 Omega .To measure the potential difference between the two ends of the resistance a voltmeter is connected .Draw the circuit

A battery of emf 1.4V and interna! resistance 2Omega is connected to a resistor of 100Omega resistance through an ammeter. The resistance of ammeter is 4/3Omega a voltmeter has also been connected to find the potential difference across the resistor. The ammeter reads 0.02 A. What is the resistance of voltmeter.

A battery of emf 1.4V and interna! resistance 2Omega is connected to a resistor of 100Omega resistance through an ammeter. The resistance of ammeter is 4/3Omega a voltmeter has also been connected to find the potential difference across the resistor. The voltmeter reads 1.10V. What is the error in the reading ?

Two cells one of emf 1.4 V and internal resistance 0.6 Omega the other of emf 2.5. V and internal resistance 0.3 Omega are connected in parallel and the combination is connected in series with an external resistance of 4 Omega . What is the current through this resistance?

Two cells , one of emf 1.2 V and internal resistance 0.5Omega the other of emf 2 V and internal resiatnce 0.1Omega are connnected in series with an external resistance of 5Omega . What is the current through this resistor ?

A cell of emf 2Vand internal resistance 1.5Omega is connected to two ends of 100 cm wire. The resistance of the wire is 0.005 Omega//cm. The potential gradient of the wire is