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A heating coil of resistance 100Omega is...

A heating coil of resistance `100Omega` is connected for 30 min to 220 V . By this time determine
(i) amount of charge flowing
( ii) amount of electrical energy consumed
(iii) amount of heat greanerted .Determine the cost of consumed electrical energy if 1 kW . h costs R.s 1 .

Text Solution

Verified by Experts

(i) Amount of charge flowing
`Q=It=(V)/(R)t=(220)/(100)xx30xx60=3960C`
(ii) Amount of electrical energy consumed ,
`W=Q.V=3960xx220=8.712xx10^(5)J`
(iii) Amount of heat generated ,
`H=(W)/(J)=(8.712xx10^(5))/(4.2)=2.074xx10^(5)"cal"`
(iv) Cost of consumed electrical energy = `(8.712xx10^(5))/(3600xx1000)xx1`
= Rs. 0.24 =24 paise
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