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2.2 kW power is supplied through a line ...

2.2 kW power is supplied through a line of `10Omega` resistance under 22000 V voltage differnce . What is the rate of heat dissipation in the line ?

Text Solution

Verified by Experts

`I=(P)/(V)=(2.2xx10^(3))/(22000)[therefore2.2kW=2.2xx10^(3)W]
`0.1A`
`therefore"Rate of heat dissipation "=I^(2)R=(0.1)^(2)xx10=0.1W`
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