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A parallel combination of three resistor...

A parallel combination of three resistors `3Omega,4Omegaand5Omega` is connected across a battery . Find which resistor will consume more electrical per energy per second .

Text Solution

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As the three resistance are connected in parallel , so the voltage drop across each of then will be same .

`therefore ` Power dissipated in `3Omega` resistance , `P_(1)=(V^(2))/(3)`
Similarly ,` P_(2)=(V^(2))/(4)and P_(3)=(V^(2))/(5)`
So , the resistance `3Omega` will consume more energy in 1 s .
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