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The potential differnce applied across a...

The potential differnce applied across a give resistor is altered that the heat produced per second increase by a Factor of 9 . By what factor does the applied potentail difference change ?

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We kown that , `H=(V^(2))/(R)t`
`" or , "(H)/(t)=(V^(2))/(R)therefore(H)/(t)propV^(2)`
It is given that heat produced per second `(H)/(t)` , increases by a factor of 9 .
Hence , applied potential V increased by a factor of 3 .
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