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Two electric bulbes P and Q have their r...

Two electric bulbes P and Q have their resistance in the ration of 1 : 2 . They are connected in series acrosse a battery . Find the ratio of the power dissipation in these bulbs .

Text Solution

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we have , `(R_(P))/(R_(Q))=(1)/(2)`
power consumed by a bulb ,
Here , current I is same for both the bulbs .
So , `=(P_(P))/(P_(Q))=(R_(P))/(R_(Q))=(1)/(2)`
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