A charge q moving in a straight line is accelerated by a potential difference V. It enters a uniform magnetic field B perpendicular to its path. Deduce in terms of V an expression for the radius of the circular path in which it travels.

A proton, a deuteron and an alpha - particle are accelerated by the same potential and then enter a uniform magnetic field perpendicularly. The ratio of radii of their circular paths will be

A charged particle moving in a straight line perpendicular to a uniform magnetic field enters the field. What will be its path in the field?

An electron (mass m, charge -e), accelerated through a potential difference V, enters normally a uniform magnetic field B. What will be the radius of the circular motion of the electron ?

Two particles of equal charge are accelerated by a potential difference and they enter a uniform magnetic field perpendicularly. The particles started rotating in circular orbits of radii 10 cm and 5 cm. What is the ratio of their masses?

The mass of an electron of charge 'e' is 'm'. The electron is moving in a straight line accelarated by a potential difference V. If enters a crossed field where E and B are the 'intensities' of electric and magnetic fields respectively acting matually perpendicular top the direction of motion of elctron . Prove that for no deflection of the electron, frac(e)(m)=frac(E^2)(2VB^2) .

A charged particle moving in a straight line parallel to a uniform magnetic field enters the field. What will be its path in the field?

A proton of mass m and charge q is moving in a plane with kinetic energy E. If there exists a uniform magnetic field B, perpendicular to the plane of the motion, the proton will move in a circular path of radius

An alpha -particle and a proton are accelerated from rest thruogh the same potential difference and both enter a uniform perpendicular magnetic field. Find the ratio of their radii of curvature.