In a compact coil of 50 turns, the current strength is 10 A and the radius of the coil is `25xx10^(-2)m`. Find the magnitude of the magnetic field at its centre.

Explanation

Number of turns, N=50, radius of the coil, `r=25xx10^(-2)`m, current strength, I =10 A. `:.` Magnetic field at the centre of the coil,
`B=(mu_(0)NI)/(2r)=(4pixx10^(-7)xx50xx10)/(2xx25xx10^(-2))`
`=1.256xx10^(-3)T`