A proton with a speed of `2xx10^(7)m.s^(-1)` enters a magnetic field of flux density `1.5Wb.m^(-2)`, making an angle of `30^(@)` with the field. The force acting on the proton is

Options

A. `2.4xx10^(-14)N`
B. `0.24xx10^(-12)N`
C. `0.024xx10^(-24)N`
D. `24xx10^(-12)N`

Explanation

We know, `|F|=qvBsintheta`
given, `B=1.5Wb.m^(-2),v=2xx10^(7)m.s^(-1),theta=30^(@),q=1.6xx10^(-19)C`
Then, `F=1.6xx10^(-19)xx2xx10^(7)xx1.5xx(1)/(2)=2.4xx10^(-12)N` None of the options are correct.