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When a current of 5 mA is passed through...

When a current of 5 mA is passed through a galvanometer having a coil of resistance `15Omega`, it show full scale defelction. The value of the resistance to be put in series range 0.10v is

A

`1.985xx10^(3) Omega`

B

`2.045xx10^(3) Omega`

C

`2.535xx10^(3) Omega`

D

`4.005xx10^(3) Omega`

Text Solution

Verified by Experts

Let the value of the resistane to be put in series be R.
`:. Vi_(g)(R_(G)+R)`
or, `R=(V)/(i_(g))-R_(G)=(10)/(5xx10^(-3))-15`
`=1.985xx10^(3) Omega`
the option A is correct
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