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A metallic rod of mass per unit length 0...

A metallic rod of mass per unit length 0.5 kg `m^(-1)` is lying horizontally on a smooth inclined plane which makes an anlge of `30^(@)` with the horizontal. The rod is not allowed to slide down by flowing a current through it when a magnetic field of induction 0.25 T is acting on it in the vertical direction. The current flowing in the rod to keep it stationary

A

`14.76A`

B

`5.98A`

C

`7.14A`

D

`11.32A`

Text Solution

Verified by Experts


For the equilibrium of the metallic rod,
` mg sin 30^(@)=Bilcos30^(@)`
`=0.5xx(9.8)/(2.25)xx tan30^(@)=11.32A`
The option D is correct.
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