An `alpha`-particle and a proton are released from the centre of a cyclotron and made to accelerate. When they are accelerated, in turn, which of the two will have higher velocity at the exit slit of the does ?

Explanation

Cyclotron frequency `n=(1)/(2pi)((q)/(m))B`
Velocity at the exist slit, `v_(0)=(qBR)/(m), i.e., v_(0) prop (q)/(m)`
As `(q)/(m)` is higher for protons, it will have a higher velocity at the exit slit.