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In Fraunhofer diffraction experiment, th...

In Fraunhofer diffraction experiment, the first minima of red light `(lambda = 600 nm )` if formed on the first maxima of another light of wavelength `lambda'` . Find the value of `lambda'`.

Text Solution

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The angle of diffraction for the first minima,
`theta = (lambda)/(a)` [ a = width of the slit]
`theta' = (2n + 1) (lambda')/(2a) = (2 xx 1 + 1) (lambda')/(2a) = (3lambda')/(2a)`
Given, `theta = theta'`
`therefore " " (lambda)/(a) = (3lambda')/(2a) or, lambda' = (2)/(3) lambda`
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