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In a double slit experiment, the two sli...

In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 mm is used.what will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern?

A

0.2 mm

B

0.1 mm

C

0.5 mm

D

0.02 mm

Text Solution

Verified by Experts

Width of the interferece fringe due to the doube slit,
`y = (D)/(d) lambda `:
D = 1m, d = 1 mm and `lambda` = 500 nm
Now, width of the central bright diffraction band due to the single slit,
`y' = (2D)/(a) lambda,` a width of the slit
According to the question,
`(2D)/(a)lambda = 10(D)/(d) lambda`
or, `a = (2)/(10)d = (2)/(10) xx 1 `mm = 0.2 mm
The option (A) is correct.
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