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If 50 kV potential difference is applie...

If 50 kV potential difference is applied across a Coolidge tube, what will be the maximum frequency of X-ray emitted from the tube? `h=6.6xx10^(-34)J*s,e=1.6xx10^(-19)C`.

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The correct Answer is:
`1.21 xx10^(19) Hz`
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Work function of a metal is 2.3eV and on 1.0 cm^(2) area of that metal, a light of intensity 8.6 xx 10^(3) W.m^(-2) is incident. That intensity is distributed equally among the wavelength 4144 Å, 4972 Å and 6216 Å . If no ray is lost due to scattering and if each of the photons of proper energy can emit photoelectrons, what will be the number of photoelectrons emitted in 2 s? (h = 6.63 xx 10^(-34) J.s, 1eV = 1.6 xx 10^(-19)J)

Under what potential difference should an electron be accelerated to obtain de Broglie, wavelength of 0.6overset@A ? (h=6.62xx10^(-34)j.s, m_e=9.1xx10^(-31) kg)

Estimate the kinetic energy of electron that hit the target in a Coolidge tube and produce X-ray of wavelength 1 Å . Given h=6.62xx10^(-34)J *s,c=3xx10^(8)m*s^(-1) .

For photoelectric emission, threshold wavelength of a metal is 2460 Å . If ultraviolet light of wavelength 1810 Å be incident on the metal, what will be the maximum kinetic energy of the emitted electrons? [Planck's constant = 6.62xx10^(-34) J.s , velocity of light in veccuum = 3xx10^(8) m.s^(-1) ]

Calculate the minimum wavelength of x-ray produced by on X-ray tube operating at 30KV [h = 6.6 xx 10^-34Js] .

Find out the photoelectric threshold wavelength of copper. Given work function of copper = 4.52eV, h = 6.6 xx 10^(-34)J.s, 1 eV = 1.6 xx 10^(-19)J

Find the wavelength of an electron having kinetic energy 10 eV. (h = 6.33 xx 10^(-34) J.s, m_(e) = 9 xx 10^(-31) kg)

The threshold wave length for any metal is 400 nm. If 200 nm of U.V. light is incident on -the object? then what will be the maximum kinetic energy if the electrons [h - 6.63xx10^-34J.S]

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