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What should be the minimum value of potential difference to be applied across a Coolidge tube for production of X-rays of wavelength 0.8 Å ?
`h=6.62xx10^(-34)J*s,e=1.6xx10^(-19) C`

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15.5 kV
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If 50 kV potential difference is applied across a Coolidge tube, what will be the maximum frequency of X-ray emitted from the tube? h=6.6xx10^(-34)J*s,e=1.6xx10^(-19)C .

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Work function of a metal is 2.3eV and on 1.0 cm^(2) area of that metal, a light of intensity 8.6 xx 10^(3) W.m^(-2) is incident. That intensity is distributed equally among the wavelength 4144 Å, 4972 Å and 6216 Å . If no ray is lost due to scattering and if each of the photons of proper energy can emit photoelectrons, what will be the number of photoelectrons emitted in 2 s? (h = 6.63 xx 10^(-34) J.s, 1eV = 1.6 xx 10^(-19)J)

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