If the longest wavelength in the ultraviolet region of hydrogen spectrum is `lambda_0` then the shortest wavelength in its infrared region is
A
`(46)/7lambda_0`
B
`(20)/3lambda_0`
C
`(36)/5lambda_0`
D
`(27)/4lambda_0`
Text Solution
Verified by Experts
The correct Answer is:
D
`lambda_0` =the longest wavelength in the ultraviolet region of hydrogen spectrum = the longest wavelength in Lyman series. `therefore 1/(lambda_0)=R(1/(1^2)-1/(2^2)) =3/4 R` or, `lambda_0 =4/(3R) ` [R=Rydberg constant] Again, if the shortest wavelength in the infrared region of hydrogen spectrum = the shortest wavelength in Paschen series= `lambda`, `1/(lambda)=R(1/3^2-1/oo^2)=R/9 or, lambda=9/R=(27)/4 lambda_0`
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